Postman Pat delivers the mail in the small village Tenhouses. This village, as you already suspected, has only one street with exactly ten houses, numbered from 1 up to and including 10.

In a certain week, Pat did not deliver any mail at two houses in the village; at the other houses he delivered mail three times each. Each working day he delivered mail at exactly four houses.

The sums of the house numbers where he delivered mail were:

on Monday: 18

on Tuesday: 12

on Wednesday: 23

on Thursday: 19

on Friday: 32

op Saturday: 25

on Sunday: he never works

The Question: Which two houses didn't get any mail that week?

Answer: If postman Pat would have delivered mail three times at each house, then the total sum of the house numbers per day would be (1+2+3+4+5+6+7+8+9+10)×3=165. Now that sum is 18+12+23+19+32+25=129. The difference is 165-129=36; divided by 3 this is 12. The sum of the house numbers where no mail was delivered is therefore 12. The following combinations are possible:

2+10

3+9

4+8

5+7

Each day at four houses the mail was delivered. On Tuesday the sum was 12. 12 can only be made from four house numbers in 2 ways:

1+2+3+6

1+2+4+5

The same holds for Friday with the sum of 32:

5+8+9+10

6+7+9+10

From this we can conclude that the house numbers 1, 2, 9 and 10 for sure have received mail, which means that the combinations 2+10 and 3+9 are not possible. Also the combination 5+7 is not possible, because mail was delivered either at house 5 or at house 7. Thus the only remaining solution is: houses 4 and 8.

N.B.: there are various possibilities for the actual post delivery of the whole week. For example:

Copyright © 2002 E.R. van Veldhoven. All rights reserved.

## Saturday, July 26, 2008

### Postman Pat

Posted by Covert Bay at 2:40 AM

Labels: Riddles/Puzzles

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